CSC 270
Homework 4
Assigned Oct. 4, due Oct. 16
What I want you to do
Write a C++ definition of a class named StringList
that holds a list of strings and can have elements added and deleted
easily.
Write a main program that reads in a sequence of
strings into a StringList (note that you do not
know in advance how many there will be, and cannot assume any
fixed limit in advance). It then computes the average length of the
strings, and prints it out;
it then sorts the list into alphabetical order, prints it out,
finds the median element in alphabetical order,
deletes it from the list, and prints out the new list along with
its average length.
The assignment should (if at all possible) be done in teams of two
students, working together at one workstation much or all of
the time. Each team should turn in one copy of the homework with both
names on it.
What's a StringList?
The tasks of reading in the list values, sorting them, and printing
them should each be done by a method of the StringList class. Other
methods of the StringList class should include
- a way to build an empty StringList
- a function that tells how many elements are in the StringList
- a way to add a specified element to a StringList (thus increasing its
size by 1)
- a way to find the n-th element of a StringList
- a way to delete a specified element of a StringList
- a way to concatenate two StringLists producing a third
This still leaves you with a lot of possible implementations. The one I'd
like you to try for this assignment is a shrinking-and-growing array:
- Shrinking and growing array, naive version
- In this approach, the StringList class actually contains an array, but
the array is dynamically allocated. When an element is added to the
StringList, it allocates a new array one element longer, copies the
elements of the old array into the new one (with the new element
inserted at the appropriate position), and de-allocates the old
one. Likewise, when an element is deleted, it allocates a new array
one element shorter, copies the elements of the old array (except the
element being deleted) into the new one, and de-allocates the old one.
This approach makes it very easy to jump around in the list and
swap elements (adjacent or not), but adding and deleting elements is
inefficient.
- Shrinking and growing array, smarter version
- As above, except that rather than allocating a new array
one element longer or shorter, and copying the whole thing,
every time an element is added or removed,
it allocates a new array several elements
longer or shorter so that it doesn't have to do it as often. The
disadvantage is that you need to keep track of how many elements are
really in the array, as well as how large the array is
right now.
For example, if the increment were 10, it would need to allocate and copy
when the first element was added, but not again until the 11th (21st,
etc.) element was added, and any insertions and deletions in between would
require no dynamic allocation of memory. Another neat way to do it is to
always grow the array by a factor of 2, and only shrink it when less than
half of it is in use.
This approach makes inserting and deleting elements more complex,
but significantly more efficient. Since the underlying data structure
is still an array, you can still jump around in the list and swap
elements (adjacent or not) very easily.
Write
your class definition in such a way as to hide the
implementation: that is, the person using your class shouldn't need
to know whether you're using singly-linked lists, doubly-linked lists,
shrinking-and-growing arrays, or something else.
How to sort the list?
There are lots of sorting algorithms in the world. The bubble-sort we
used in the previous problem is fairly simple, but not very efficient.
Get your program to work correctly using the bubble-sort from the
previous homework, and then, for extra credit, try
Quicksort and/or Mergesort.
Quicksort
The idea here is to pick an element of the list -- called the "pivot" --
and divide the list into three categories: the elements less than the pivot,
the elements equal to the pivot, and the elements greater than
the pivot. To do this, you may want to write a categorize
method that "returns" three lists (by taking in three List &
parameters and assigning them). Once this is done, recursively sort
the elements-less list and the elements-greater list (the elements-equal
list, having only one value in it, is already sorted). Then you can
simply concatenate the sorted elements-less list, the elements-equal
list, and the sorted elements-greater list and get the final answer.
Mergesort
Mergesort, too, involves dividing the whole list into smaller pieces,
sorting the pieces recursively, and putting them back together.
But rather than dividing the list into those less than, equal to, and
greater than a pivot, we'll just divide the list into the first half and
the second half. Sort each of them recursively. Now you have two
sorted lists, and need to put them together. Imagine each one is a
sorted deck of cards: to combine two sorted decks into one, you look at
the top card in each deck and take the smaller of the two, then do that
again, and again, until one or the other deck becomes empty, at which
point you take the entire remaining deck.
Last modified:
Stephen Bloch / sbloch@adelphi.edu